Integrand size = 10, antiderivative size = 162 \[ \int x^2 \text {arcsinh}(a x)^4 \, dx=-\frac {160 x}{27 a^2}+\frac {8 x^3}{81}+\frac {160 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)}{27 a^3}-\frac {8 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)}{27 a}-\frac {8 x \text {arcsinh}(a x)^2}{3 a^2}+\frac {4}{9} x^3 \text {arcsinh}(a x)^2+\frac {8 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a^3}-\frac {4 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a}+\frac {1}{3} x^3 \text {arcsinh}(a x)^4 \]
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Time = 0.24 (sec) , antiderivative size = 162, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {5776, 5812, 5798, 5772, 8, 30} \[ \int x^2 \text {arcsinh}(a x)^4 \, dx=-\frac {4 x^2 \sqrt {a^2 x^2+1} \text {arcsinh}(a x)^3}{9 a}-\frac {8 x^2 \sqrt {a^2 x^2+1} \text {arcsinh}(a x)}{27 a}-\frac {8 x \text {arcsinh}(a x)^2}{3 a^2}-\frac {160 x}{27 a^2}+\frac {8 \sqrt {a^2 x^2+1} \text {arcsinh}(a x)^3}{9 a^3}+\frac {160 \sqrt {a^2 x^2+1} \text {arcsinh}(a x)}{27 a^3}+\frac {1}{3} x^3 \text {arcsinh}(a x)^4+\frac {4}{9} x^3 \text {arcsinh}(a x)^2+\frac {8 x^3}{81} \]
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Rule 8
Rule 30
Rule 5772
Rule 5776
Rule 5798
Rule 5812
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} x^3 \text {arcsinh}(a x)^4-\frac {1}{3} (4 a) \int \frac {x^3 \text {arcsinh}(a x)^3}{\sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {4 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a}+\frac {1}{3} x^3 \text {arcsinh}(a x)^4+\frac {4}{3} \int x^2 \text {arcsinh}(a x)^2 \, dx+\frac {8 \int \frac {x \text {arcsinh}(a x)^3}{\sqrt {1+a^2 x^2}} \, dx}{9 a} \\ & = \frac {4}{9} x^3 \text {arcsinh}(a x)^2+\frac {8 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a^3}-\frac {4 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a}+\frac {1}{3} x^3 \text {arcsinh}(a x)^4-\frac {8 \int \text {arcsinh}(a x)^2 \, dx}{3 a^2}-\frac {1}{9} (8 a) \int \frac {x^3 \text {arcsinh}(a x)}{\sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {8 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)}{27 a}-\frac {8 x \text {arcsinh}(a x)^2}{3 a^2}+\frac {4}{9} x^3 \text {arcsinh}(a x)^2+\frac {8 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a^3}-\frac {4 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a}+\frac {1}{3} x^3 \text {arcsinh}(a x)^4+\frac {8 \int x^2 \, dx}{27}+\frac {16 \int \frac {x \text {arcsinh}(a x)}{\sqrt {1+a^2 x^2}} \, dx}{27 a}+\frac {16 \int \frac {x \text {arcsinh}(a x)}{\sqrt {1+a^2 x^2}} \, dx}{3 a} \\ & = \frac {8 x^3}{81}+\frac {160 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)}{27 a^3}-\frac {8 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)}{27 a}-\frac {8 x \text {arcsinh}(a x)^2}{3 a^2}+\frac {4}{9} x^3 \text {arcsinh}(a x)^2+\frac {8 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a^3}-\frac {4 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a}+\frac {1}{3} x^3 \text {arcsinh}(a x)^4-\frac {16 \int 1 \, dx}{27 a^2}-\frac {16 \int 1 \, dx}{3 a^2} \\ & = -\frac {160 x}{27 a^2}+\frac {8 x^3}{81}+\frac {160 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)}{27 a^3}-\frac {8 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)}{27 a}-\frac {8 x \text {arcsinh}(a x)^2}{3 a^2}+\frac {4}{9} x^3 \text {arcsinh}(a x)^2+\frac {8 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a^3}-\frac {4 x^2 \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3}{9 a}+\frac {1}{3} x^3 \text {arcsinh}(a x)^4 \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 112, normalized size of antiderivative = 0.69 \[ \int x^2 \text {arcsinh}(a x)^4 \, dx=\frac {8 a x \left (-60+a^2 x^2\right )-24 \left (-20+a^2 x^2\right ) \sqrt {1+a^2 x^2} \text {arcsinh}(a x)+36 a x \left (-6+a^2 x^2\right ) \text {arcsinh}(a x)^2-36 \left (-2+a^2 x^2\right ) \sqrt {1+a^2 x^2} \text {arcsinh}(a x)^3+27 a^3 x^3 \text {arcsinh}(a x)^4}{81 a^3} \]
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Time = 0.04 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.86
method | result | size |
derivativedivides | \(\frac {\frac {a^{3} x^{3} \operatorname {arcsinh}\left (a x \right )^{4}}{3}+\frac {8 \operatorname {arcsinh}\left (a x \right )^{3} \sqrt {a^{2} x^{2}+1}}{9}-\frac {4 a^{2} x^{2} \operatorname {arcsinh}\left (a x \right )^{3} \sqrt {a^{2} x^{2}+1}}{9}-\frac {8 a x \operatorname {arcsinh}\left (a x \right )^{2}}{3}+\frac {160 \,\operatorname {arcsinh}\left (a x \right ) \sqrt {a^{2} x^{2}+1}}{27}-\frac {160 a x}{27}+\frac {4 a^{3} x^{3} \operatorname {arcsinh}\left (a x \right )^{2}}{9}-\frac {8 \,\operatorname {arcsinh}\left (a x \right ) \sqrt {a^{2} x^{2}+1}\, a^{2} x^{2}}{27}+\frac {8 a^{3} x^{3}}{81}}{a^{3}}\) | \(140\) |
default | \(\frac {\frac {a^{3} x^{3} \operatorname {arcsinh}\left (a x \right )^{4}}{3}+\frac {8 \operatorname {arcsinh}\left (a x \right )^{3} \sqrt {a^{2} x^{2}+1}}{9}-\frac {4 a^{2} x^{2} \operatorname {arcsinh}\left (a x \right )^{3} \sqrt {a^{2} x^{2}+1}}{9}-\frac {8 a x \operatorname {arcsinh}\left (a x \right )^{2}}{3}+\frac {160 \,\operatorname {arcsinh}\left (a x \right ) \sqrt {a^{2} x^{2}+1}}{27}-\frac {160 a x}{27}+\frac {4 a^{3} x^{3} \operatorname {arcsinh}\left (a x \right )^{2}}{9}-\frac {8 \,\operatorname {arcsinh}\left (a x \right ) \sqrt {a^{2} x^{2}+1}\, a^{2} x^{2}}{27}+\frac {8 a^{3} x^{3}}{81}}{a^{3}}\) | \(140\) |
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Time = 0.26 (sec) , antiderivative size = 154, normalized size of antiderivative = 0.95 \[ \int x^2 \text {arcsinh}(a x)^4 \, dx=\frac {27 \, a^{3} x^{3} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right )^{4} + 8 \, a^{3} x^{3} - 36 \, \sqrt {a^{2} x^{2} + 1} {\left (a^{2} x^{2} - 2\right )} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right )^{3} + 36 \, {\left (a^{3} x^{3} - 6 \, a x\right )} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right )^{2} - 24 \, \sqrt {a^{2} x^{2} + 1} {\left (a^{2} x^{2} - 20\right )} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right ) - 480 \, a x}{81 \, a^{3}} \]
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Time = 0.52 (sec) , antiderivative size = 158, normalized size of antiderivative = 0.98 \[ \int x^2 \text {arcsinh}(a x)^4 \, dx=\begin {cases} \frac {x^{3} \operatorname {asinh}^{4}{\left (a x \right )}}{3} + \frac {4 x^{3} \operatorname {asinh}^{2}{\left (a x \right )}}{9} + \frac {8 x^{3}}{81} - \frac {4 x^{2} \sqrt {a^{2} x^{2} + 1} \operatorname {asinh}^{3}{\left (a x \right )}}{9 a} - \frac {8 x^{2} \sqrt {a^{2} x^{2} + 1} \operatorname {asinh}{\left (a x \right )}}{27 a} - \frac {8 x \operatorname {asinh}^{2}{\left (a x \right )}}{3 a^{2}} - \frac {160 x}{27 a^{2}} + \frac {8 \sqrt {a^{2} x^{2} + 1} \operatorname {asinh}^{3}{\left (a x \right )}}{9 a^{3}} + \frac {160 \sqrt {a^{2} x^{2} + 1} \operatorname {asinh}{\left (a x \right )}}{27 a^{3}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \]
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Time = 0.21 (sec) , antiderivative size = 143, normalized size of antiderivative = 0.88 \[ \int x^2 \text {arcsinh}(a x)^4 \, dx=\frac {1}{3} \, x^{3} \operatorname {arsinh}\left (a x\right )^{4} - \frac {4}{9} \, a {\left (\frac {\sqrt {a^{2} x^{2} + 1} x^{2}}{a^{2}} - \frac {2 \, \sqrt {a^{2} x^{2} + 1}}{a^{4}}\right )} \operatorname {arsinh}\left (a x\right )^{3} - \frac {4}{81} \, {\left (2 \, a {\left (\frac {3 \, {\left (\sqrt {a^{2} x^{2} + 1} x^{2} - \frac {20 \, \sqrt {a^{2} x^{2} + 1}}{a^{2}}\right )} \operatorname {arsinh}\left (a x\right )}{a^{3}} - \frac {a^{2} x^{3} - 60 \, x}{a^{4}}\right )} - \frac {9 \, {\left (a^{2} x^{3} - 6 \, x\right )} \operatorname {arsinh}\left (a x\right )^{2}}{a^{3}}\right )} a \]
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Exception generated. \[ \int x^2 \text {arcsinh}(a x)^4 \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int x^2 \text {arcsinh}(a x)^4 \, dx=\int x^2\,{\mathrm {asinh}\left (a\,x\right )}^4 \,d x \]
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